# SATII数学专题分析——Lines and Distance |南京留学中介

Lines and distance are fundamental to coordinate geometry, not to mention to the Math IC test. Even the most complicated coordinate geometry question uses the concepts covered in the next few sections.南京留学中介 | 南京留学中介排名 | 南京美国留学中介 |  南京出国留学中介 | 南京留学机构
Distance

Measuring distance in the coordinate plane is made possible thanks to the Pythagorean theorem. If you are given two points, (x1,y1), and (x2,y2), their distance from each other is given by the following formula: The diagram below shows how the Pythagorean theorem plays a role in the formula. The distance between two points can be represented by the hypotenuse of a right triangle whose legs are lengths (x2 – x1) and (y2 – y1).
To calculate the distance from (4, –3) to (–3, 8), plug the coordinates into the formula: The distance between the points is , which equals approximately 13.04. You can double-check this answer by plugging it back into the Pythgorean theorem.

Finding Midpoints

The midpoint between two points in the coordinate plane can be calculated using a formula. If the endpoints of a line segment are (x1y1) and (x2y2), then the midpoint of the line segment is: In other words, the x- and y-coordinates of the midpoint are the averages of the x- and y-coordinates of the endpoints.

Here’s a practice question:
What is the midpoint of the line segment whose endpoints are (6, 0) and (3, 7)?

To solve, all you need to do is plug the points given into the midpoint formula. x1 = 6, y1 = 0, x2 = 3, and y2 = 7: 南京留学中介 | 南京留学中介排名 | 南京美国留学中介 |  南京出国留学中介 | 南京留学机构

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